Wheel Pulley Set
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| 4 Pc Gear Puller Steering Wheel Pulley Set In Outside CR V 3 4 6 8 Pullers | |
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Wheel Pulley Set
What is needed to make a 1750 rpm motor turn a 26" wheel at 5mph?
My father is trying to create a ski pulley system to pull him up a hill. Basically, set the motor at the bottom, climb up and set the pulley on the other end, then you can just ski down and ride back up.
He has a 1750 RPM electric motor with a 1 1/4" shaft and a 26" bicycle wheel. He wants the lift to go a decent speed (5mph, or so). Is there a way to create a high torque lift system with those components and gears or pulleys, and if so, what would still be needed (think cheap)? How would he incorporate these parts into a lift system?
A 26" diameter wheel has a circumference of 6.8 feet
5 mph = 26,400 feet/hour or 440 feet/minute.
The wheel must therefore turn at 64.7 rpm
1750/64.7=27
You will need a reduction ratio of 27:1 Torque will increase by the same ratio.
I can think of three ways of achieving this: 1. Use a double-pass pulley arrangement using a jack-shaft and 4 pulleys, 2 belts. 2. Weld a second wheel to the first as a pulley, and loop the belt around the motor shaft (this would give you about 20:1 - a little fast 3. find an old small-car manual transmission which would give you a 5:1 or 7:1 ratio in 'high', and make up the difference with a belt and 2 pulleys. I'm sure there are other ways, but these come quickly to mind!
Performance Machine - Heathen Wheel Set & Super Gas Air Cleaner